TPTP Problem File: LCL682+1.001.p

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%------------------------------------------------------------------------------
% File     : LCL682+1.001 : TPTP v8.1.0. Released v4.0.0.
% Domain   : Logic Calculi (Modal Logic)
% Problem  : In S4, path through a labyrinth, size 1
% Version  : Especial.
% English  :

% Refs     : [BHS00] Balsiger et al. (2000), A Benchmark Method for the Pro
%          : [Kam08] Kaminski (2008), Email to G. Sutcliffe
% Source   : [Kam08]
% Names    : s4_path_p [BHS00]

% Status   : Theorem
% Rating   : 0.00 v5.3.0, 0.09 v5.2.0, 0.00 v4.1.0, 0.06 v4.0.1, 0.05 v4.0.0
% Syntax   : Number of formulae    :    3 (   1 unt;   0 def)
%            Number of atoms       :   25 (   0 equ)
%            Maximal formula atoms :   21 (   8 avg)
%            Number of connectives :   43 (  21   ~;  20   |;   1   &)
%                                         (   0 <=>;   1  =>;   0  <=;   0 <~>)
%            Maximal formula depth :   16 (   8 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    7 (   7 usr;   0 prp; 1-2 aty)
%            Number of functors    :    0 (   0 usr;   0 con; --- aty)
%            Number of variables   :   18 (  17   !;   1   ?)
% SPC      : FOF_THM_EPR_NEQ

% Comments : A naive relational encoding of the modal logic problem into
%            first-order logic.
%------------------------------------------------------------------------------
fof(reflexivity,axiom,
    ! [X] : r1(X,X) ).

fof(transitivity,axiom,
    ! [X,Y,Z] :
      ( ( r1(X,Y)
        & r1(Y,Z) )
     => r1(X,Z) ) ).

fof(main,conjecture,
    ~ ? [X] :
        ~ ( ~ ! [Y] :
                ( ~ r1(X,Y)
                | ~ ( ~ ! [X] :
                          ( ~ r1(Y,X)
                          | p16(X) )
                    | ~ ! [X] :
                          ( ~ r1(Y,X)
                          | p12(X) )
                    | ~ ! [X] :
                          ( ~ r1(Y,X)
                          | p14(X) )
                    | ~ ! [X] :
                          ( ~ r1(Y,X)
                          | p12(X) ) ) )
          | ! [Y] :
              ( ~ r1(X,Y)
              | ! [X] :
                  ( ~ r1(Y,X)
                  | p15(X) ) )
          | ! [Y] :
              ( ~ r1(X,Y)
              | ! [X] :
                  ( ~ r1(Y,X)
                  | p13(X) ) )
          | ! [Y] :
              ( ~ r1(X,Y)
              | ! [X] :
                  ( ~ r1(Y,X)
                  | p12(X) ) )
          | ! [Y] :
              ( ~ r1(X,Y)
              | ! [X] :
                  ( ~ r1(Y,X)
                  | p11(X) ) ) ) ).

%------------------------------------------------------------------------------